In the second iteration, line 1 might give 67 (added 57 this time), line 2 = 57, line 3 = ..... 0.

DAMN... DAMN... DAMN ONE MORE TIME. It is me who should go and study comp.sci. This is the integer arithmetic... Fuck.

OK,
carac2 = carac2 + resultat[cpt3] ; (1) - you say, for example, carac2 will be 67. OK. Fine.
Then:
resultat[cpt3] = carac2 % 100 ; (2)
the operation "%" in C/C++ is the same as mod in number theory.
So, 67 mod 100 = 67 - not 57 as you are trying to say if I understood you properly, of course...
Then:
carac2 = carac2 div 100 -> carac2 = 67/100 - this is normally not 0, of course, BUT this is computer arithmetic and the result is rounded up, so it will be floor(67/100) which is 0 indeed. So you are partially right and I'm wrong. My bad.