decryption problem with MD5

[anon_c]

q1 : MD5 string have a special form to reduce above possible string ?

unfortunately, no...


you wrote:
7D=44+39 ==>D9
7D=45+38 ==>E8
7D=46+37 ==>F7

but can't
7D=39+44 ==>9D
7D=38+45 ==>8E
7D=37+46 ==>7F

also be valid solutions?

my understanding from your first two posts was that you wanted a solution for each byte taken from a md5 hash, given that each byte is the sum of 2 "ascii code" for values in the range of possible Hex number ['1'..'9', 'A'..'F'] (thus 0x30-0x39 and 0x41-0x46) ?

this would already limits the values of the bytes (from the md5) to 0x60-0x92.. Do you really have a md5 hashing that always give bytes in this limited range? Please, give an example of a md5 used in your example then.

Now you wrote "orginal md5 string or 16 key value not used". From where does the 7D comes from then? Confusing...