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#1
06-02-2016, 14:52
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@Conquest
Not exactly. Bear in mind the Int64 precision. Say you work in 16 bits You want X^7 == 8680 Solve for the 7th root and you will get in decimal 4.44712�� But a valid solution would be for instance: 4A (74 dec) because the result of 4A ^ 7 is 8680 in 16bit @Dila I don��t see any other option than brute force AC 
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#2
06-02-2016, 16:41
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E80E9AAC619831FB
And no, I didn't bruteforce 20.000 years, it's just simple math. Just as a small hint: If "x^7" is supposed to end on the digit "3", could "x" ever be a multiple of "2"? Answer: No. You've reduced the number of possible values for "x" by 50%. Last edited by Kerlingen; 06-02-2016 at 19:40. Reason: Of course it's 20k (=20.000) years. 20 would be far too low. ;)
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