Find the secret key for this function

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Find the secret key for this function

06-02-2016, 16:41

Kerlingen

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E80E9AAC619831FB

And no, I didn't bruteforce 20.000 years, it's just simple math.

Just as a small hint:
If "x^7" is supposed to end on the digit "3", could "x" ever be a multiple of "2"?
Answer: No.
You've reduced the number of possible values for "x" by 50%.

Last edited by Kerlingen; 06-02-2016 at 19:40. Reason: Of course it's 20k (=20.000) years. 20 would be far too low. ;)

The Following User Says Thank You to Kerlingen For This Useful Post:
dila (06-03-2016)

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