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#1
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It will work regardless. I've tried it, using my own volume serial of course.
There is does no check against the random bytes. Code:
var_8020 = GetVolumeInformation("C:\", String$(256, False), 255, global_005C507C, global_005C5084, global_005C5080, String$(256, False), 255)
Code:
var_2C = Proc_23_0_565AB7(Mid(var_3C, 17, Len(var_3C)), Mid(var_3C, 1, 16), 0) Code:
var_8050 = Proc_23_0_565AB7(Proc_24_1_56681B(GetSetting("NDataScan", "Activation", "RegCode", 10), var_CC, 80020004h), "Lilys", var_C4)
var_3C = var_8050
var_34 = Proc_23_0_565AB7(Mid(var_3C, 17, Len(var_3C)), Mid(var_3C, 1, 16), 0)
var_34 = Left(var_34, Len(var_34)(-1))
var_34 = Right(var_34, Len(var_34)(-1))
Code:
If CBool((var_2C = var_34) And (var_2C = Str(global_005C507C)) And (var_34 = Str(global_005C507C))) Then var_40 = "NDSI has been sucessfully activated. Please restart NDSI." compare the decoded VolumeSerial# from our input with the decoded VolumeSerial# from registry, less the left and right chars. check 2 -> var_2C = Str(global_005C507C) compare the decoded VolumeSerial# from our input with the GetVolumeInformation VolumeSerial# check 3 -> var_34 = Str(global_005C507C) decoded VolumeSerial# from registry, less the left and right chars with the GetVolumeInformation VolumeSerial# as i said before, check 3 is redundant. It will always pass as the program generated it . |
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niculaita (12-28-2021) | ||
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#2
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Quote:
That is because the random bytes used to encrypt the VolumeSerialNum in the 1.encryption are in themselves included in each case in the 2.encryption leading to the final RegCode and the ActivKey respectively. Therefore an ActivKey generated with the same VolumeSerialNum of a target machine will work regardless of the RegCode. This is a valid point. |
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